Django – 前端提交数据, 后端接收并入库简例 (ModelForm)

1. models.py

 

class Boss(models.Model):
    name = models.CharField(verbose_name="姓名", max_length=64)
    age = models.IntegerField(verbose_name="年龄")
    img = models.CharField(verbose_name="头像", max_length=256)

 

这种写法需要在view_name.py文件中去处处理 待保存文件的路径问题, 并调用create方法.

media_file_path = os.path.join("media", image_object.name)
print(media_file_path)
f = open(media_file_path, mode="wb")
for chunk in image_object.chunks():
    f.write(chunk)
    f.close()

models.Boss.objects.create(
    name = form.cleaned_data['name'],
    age = form.cleaned_data['age'],
    img = media_file_path,

 

 

class City(models.Model):
    name = models.CharField(verbose_name="名称", max_length=64)
    count = models.IntegerField(verbose_name="人口")

    # 此处写成"FileField", 而不是"IntegerField", 这样FileField会多出upload_to='目录名'属性, 在入库时可快速将图片保存到该目录
    logo = models.FileField(verbose_name="logo", max_length=256, upload_to='city/')

 

2. view_name.py

class UpModelForm(BootStrapModelForm):
    class Meta:

        model = models.City
        fields = "__all__"

def upload_model_form(request):
    title = "ModelForm上传"
    if request.method == "GET":
        form = UpModelForm()
        return render(request, 'upload_form.html', {'form': form, "title": title})


    form = UpModelForm(data=request.POST, files=request.FILES)
    if form.is_valid():
        form.save()
        return HttpResponse('成功')

 

可以看到这种写法非常简捷,  保存路径已在创建model时设置, 而保存数据只需form.save()即可.

3. 结果验证

• 保存路径: logo = models.FileField(verbose_name=”logo”, max_length=256, upload_to=’city/’)
• 如何保存: form.save()

 

 

4. 前置条件

配置media目录. (实际使用中, 由于目录位置等差异, 根据实际情调整.)

4.1 setting.py

MEDIA_ROOT = os.path.join(BASE_DIR, "media")
MEDIA_URL = "/media/"

 

4.2 urls.py 路由

 

from django.views.static import serve
from django.conf import settings
re_path(r'^media/(?P<path>.*)$', serve, {"document_root": settings.MEDIA_ROOT}, name='media'),

 

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